A woman, 110 lbs, stands on a high raised platform with a large hole in the floor.
The drop from the hole to the lower ground is 10 feet.
She has wrapped a length of rope three times around her chest. The rest of the rope is flung up over a beam 12 feet above the platform, and four feet from the hole. The far end reaches back to the platform floor with 5 feet spare, and its end is formed into a noose.
A man, 140 lbs, is climbing through the hole. The woman places the noose around his neck, and pushes him backwards, so that he drops through the hole.
My question - what happens mechanically to the woman? This is how I see it:
She is yanked backward and off the floor to dangle at a certain height - but how high will she be before she balances the weight of the man?
Bear in mind, the rope is through the hole, but it is suspended from the beam at an angle, and there will be friction as it meets the edge of the hole.
I don't need an exact answer - I just need to know whether
(a) I'm correct in assuming she would actually be suspended off the ground, as she is lighter than the man's weight? I'm tempted to say that her toes would be clear from the ground by few inches, but would she rise higher?
(b) she wouldn't shoot up so high that the man would reach the lower ground - she would have to rise 4 feet for this?
I actually have a diagram, but the forum editor removes spaces so it makes no sense Hope above description is not incomprehensible.
The drop from the hole to the lower ground is 10 feet.
She has wrapped a length of rope three times around her chest. The rest of the rope is flung up over a beam 12 feet above the platform, and four feet from the hole. The far end reaches back to the platform floor with 5 feet spare, and its end is formed into a noose.
A man, 140 lbs, is climbing through the hole. The woman places the noose around his neck, and pushes him backwards, so that he drops through the hole.
My question - what happens mechanically to the woman? This is how I see it:
She is yanked backward and off the floor to dangle at a certain height - but how high will she be before she balances the weight of the man?
Bear in mind, the rope is through the hole, but it is suspended from the beam at an angle, and there will be friction as it meets the edge of the hole.
I don't need an exact answer - I just need to know whether
(a) I'm correct in assuming she would actually be suspended off the ground, as she is lighter than the man's weight? I'm tempted to say that her toes would be clear from the ground by few inches, but would she rise higher?
(b) she wouldn't shoot up so high that the man would reach the lower ground - she would have to rise 4 feet for this?
I actually have a diagram, but the forum editor removes spaces so it makes no sense Hope above description is not incomprehensible.