Mathematical Poetry Challenge

kborsden

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Pure mathematics is in its way, the poetry of logical ideas. ~Albert Einstein

Don't be scared off by the thread title. This is actually an easy game. I promise :) The idea is to produce mathematical equations, formulas, expressions that rhyme and produce an actual value. Sounds complicated, right? Well, see the examples below:

dozen.png


A Dozen, a Gross and a Score,
plus three times the square root of four,
divided by seven,
plus five times eleven,
equals nine squared and not a bit more.
~ Jon Saxton
_________________________________

int.png


The Integral of tee-squared dee tee,
from one to the cube root of three,
times half the cosine,
of three-pi over nine,
is the log of the sixth root of e.
~Anon
_________________________________

Our poems don't have to be limericks like the examples. That would get annoying very quickly.

So the rules are:
  • you need to be able to render the poem in mathematical format
  • any rhyme scheme and metre combination will do (haiku also doable as form without rhyme)
  • be as complex or as simple as you like
  • the maths must be correct
  • you must post both the mathematical formula and the poem in words
  • you can mix and match mathematical, colloquial and common references


Here's a link to an editor for generating the image:
http://www.homeschoolmath.net/worksheets/equation_editor.php
_________________________________

To prove that this can be done, here's mine:

mixmatch_.png


Six times twenty-four divided by 2—
minus 8 squared plus four, and then 2 more,
when multiplied by three and by five through,
gives us only one half of two point four.
_________________________________

Now, you go ;)

I think I'll try a sonnet next...
 
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kborsden

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mathsonnet.png


Take twice the product of six times three,
plus three times two squared, and multiply by four.
Divide that by two, add on two by three—
and onto that add just a single score.

Take away the product of two times six
multiplied by the square root of sixteen,
with yet another two score to it;
add the sum of minus one plus thirteen.

Divide it by the sum of two and four
plus again twice the sum of no number
added to eleven by half a score
multiplied by two, take off a hundred.

This equals eighteen and two more, divided
by sixteen when a four is provided.
 
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jaus tail

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gif.latex


two plus two equals four
that is something we all know
but if you multiply the sum
with a vertical bum

the sum that you get
if added with three
and divided by seven
gives us a number
that's six short from eleven
 

kborsden

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Triolet Mathiolet

triolet.png


So, ex plus ay bee to the power of four
is not equal to ex squared plus ay bee
because ex plus bee is still three ex more
than ex plus ay bee to the power of four.
Thus ay is nought if ex plus bee is four
therefore ex is one and bee must be three—
if ex plus ay bee to the power of four
is not equal to ex squared plus ay bee.

_________________________________

ETA: I'm not 100% sure the mathematical markup is correct; it is for my programmer's brain, but if incorrect, I'd appreciate being told so it can be corrected.
 
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ZachJPayne

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This is beautiful and horrifying, like a 28-car pileup dusted by a light snowfall.

I'll have to see if I can come up with something. Unfortunately, I am not a math person.
 

LucidCrux

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Alright. I took up the challenge. This is ridiculously hard but completely consuming and fun at the same time. Unfortunately, I don't think there is a mathematical equivalent for bit shifting, so I used programming conventions in the equation at the end. Some of this was not planned, it was happy accidents I just took advantage of.

Mammaries

'X' is five over two on the floor.
Then times it by three raised to four.
Now take away seven, then add on eleven,
and how 'bout a baker's bit more?
(Go team prime!)

The binary here, it gets shifty.
Go right once, and not 'cause it's thrifty.
Then back to the left, a triplet for heft,
now binary's done, ain't that nifty?
(What a rhyme!)

Find the answer of nine power two
and then times by what came this far through.
Product eight, seven, six, and add it to the mix
And by golly, look how the time flew.
(Weren't it great?)

Numbers one to eleven were covered (plus omen).
But where is the ten, you poor showman?
With Romans at heart, look back to the start,
finally take the solution and home in.
(Simply rotate.)

-----------

If you want to see the "answer" and the numbers as the lines go... here it is:

X = (((floor( 5 / 2 ) * (3 ^ 4) - 7 + 11 + 13 ) >> 1 ) << 3 ) * ( 9 ^ 2 ) + ( 8 * 7 * 6)

2
162
166
179 (prime) along with 7, 11, 13

10110011 is 179 in binary
1011001 (89)
1011001000
and that back to normal is 712

81
57,672
58008
If you ever owned a calculator, you should know that number.

As always, feedback is welcome. :D
 

jaus tail

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I dont have words to give a feedback. It's something. Not sure what to say, but you've put a lot of effort.
 

kborsden

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LucidCrux, well done. you know, there are only 10 kinds of people in this world: those who understand binary, and those who don't.

I've been meaning to add something to this thread for a while, but I thought it was dead. Thanks for breathing some life into it.